Answer
Vertex: $(0,0)$
Focus: $(0,1)$
Directrix: $y=-1$
See graph
Work Step by Step
We are given the parabola:
$x^2=4y$
The standard form of the equation is:
$(x-h)^2=4p(y-k)$
Determine $h,k,p$:
$h=0$
$k=0$
$4p=4\Rightarrow p=1$
Determine the vertex:
$(h,k)=(0,0)$
Determine the focus:
$(h,k+p)=(0,0+1)=(0,1)$
Determine the directrix:
$y=k-p$
$y=0-1$
$y=-1$
Determine the latus rectum points:
$y=1$
$x^2=4(1)$
$x^2=4$
$x=\pm 2$
$\Rightarrow (-2,1),(2,1)$
Plot the points, plot the directrix, and graph the parabola: