## University Calculus: Early Transcendentals (3rd Edition)

a) $\int^{2}_{2}g(x)dx=0$ (for zero width interval, integral=0) b) $\int^{1}_{5}g(x)dx=-\int^{5}_{1}g(x)dx=-8$ c) $\int^{2}_{1}3f(x)dx=3\int^{2}_{1}f(x)dx$ $=3\times-4=-12$ d) $\int^{5}_{2}f(x)dx=\int^{5}_{1}f(x)dx-\int^{2}_{1}f(x)dx$ $=6-(-4)=10$ e) $\int^{5}_{1}[f(x)-g(x)]dx$ $=\int^{5}_{1}f(x)dx-\int^{5}_{1}g(x)dx=6-8=-2$ f) $\int^{5}_{1}[4f(x)-g(x)]dx$ $=4\int^{5}_{1}f(x)dx-\int^{5}_{1}g(x)dx$ $=4\times6-8=16$