University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 29



Work Step by Step

Because $1\lt2$, by Equation (2): $\int_{1}^{\sqrt 2} x dx=\frac{(\sqrt 2)^2}{2}-\frac{1^2}{2}=\frac{2}{2}-\frac{1}{2}=\frac{1}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.