Answer
7
Work Step by Step
$\int^{2}_{1}3u^{2}du= 3\int^{2}_{1}u^{2}du$
$=3\times[\frac{2^{3}}{3}-\frac{1^{3}}{3}]=3(\frac{8}{3}-\frac{1}{3})$
$=3\times\frac{7}{3}=7$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 47
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