University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 42



Work Step by Step

According to Rule (3) in Table 5.4 : $\int_{0}^{2} 5xdx=5\cdot\int_{0}^{2} xdx$. Because $0\lt2$, by Equation (2): $=5\cdot\int_{0}^{2} xdx=5\cdot(\frac{2^2}{2}-\frac{0^2}{2})=5\cdot(\frac{4}{2}-\frac{0}{2})=5\cdot2=10$
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