Answer
$-\frac{7}{4}$
Work Step by Step
$\int^{1}_{2}(1+\frac{z}{2})dz=\int^{1}_{2}dz+\frac{1}{2}\int^{1}_{2}zdz $
$=(1-2)+\frac{1}{2}(\frac{1^{2}}{2}-\frac{2^{2}}{2})$
$=-1+(-\frac{3}{4})=-\frac{7}{4}$
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