Answer
$-\frac{7}{4}$
Work Step by Step
$\int^{1}_{2}(1+\frac{z}{2})dz=\int^{1}_{2}dz+\frac{1}{2}\int^{1}_{2}zdz $
$=(1-2)+\frac{1}{2}(\frac{1^{2}}{2}-\frac{2^{2}}{2})$
$=-1+(-\frac{3}{4})=-\frac{7}{4}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 45
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