University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 13


a) 4 b) -4

Work Step by Step

a) $\int^{4}_{0}f(z)dz= \int^{3}_{0}f(z)dz+\int^{4}_{3}f(z)dz$ $⇒7=3+\int^{4}_{3}f(z)dz $ $⇒\int^{4}_{3}f(z)dz= 7-3=4 $. b) $\int^{3}_{4}f(t)dt=\int^{3}_{4}f(z)dz= -\int^{4}_{3}f(z)dz$ $=-4$
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