University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 40



Work Step by Step

We know that $\int^{b}_{0}x^{2}dx= \frac{b^{3}}{3}$ Then $\int^{3b}_{0}x^{2}dx= \frac{(3b)^{3}}{3}=\frac{27b^{3}}{3}=9b^{3}$
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