Answer
0
Work Step by Step
$\int^{0}_{3}(2z-3)dz=2\int^{0}_{3}zdz-3\int^{0}_{3}dz $
$=2(\frac{0^{2}}{2}-\frac{3^{2}}{2})-3(0-3)$
$=-9+9=0$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.3 - The Definite Integral - Exercises - Page 309: 46
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