University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.3 - The Definite Integral - Exercises: 53

Answer

$b^2$

Work Step by Step

$\int_{0}^{b} 2xdx=[x^2]_{0}^{b}=b^2-0^2=b^2$
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