Answer
$$1$$
Work Step by Step
\begin{align*} \int_{-\infty}^{0} e^{-|x|} d x&=\int_{-\infty}^{0} e^{x} d x\\
&=\lim _{b \rightarrow-\infty}\left[e^{x}\right]_{b}^{0}\\
&=\lim _{b \rightarrow-\infty}\left(1-e^{b}\right)\\&=(1-0)=1
\end{align*}
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 8: Techniques of Integration - Section 8.8 - Improper Integrals - Exercises 8.8 - Page 501: 23
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