Answer
$\dfrac{\sec\pi x\tan\pi x}{\pi}+\dfrac{1}{\pi}\ln|\sec \pi x+\tan\pi x|+C$
Work Step by Step
Apply the Reduction Formula:
$\int\sec^naxdx=\dfrac{\sec^{(n-2)}ax\tan ax}{a(n-1)}+\dfrac{n-2}{n-1}\int\sec^{n-2}axdx$
Let $I=2[\dfrac{\sec\pi x\tan \pi x}{2\pi}+\dfrac{1}{2}\int\sec\pi xdx] \\=\dfrac{\sec\pi x\tan\pi x}{\pi}+\int\sec\pi xdx \\=\dfrac{\sec\pi x\tan\pi x}{\pi}+\dfrac{1}{\pi}\ln|\sec \pi x+\tan\pi x|+C$