Answer
$\sqrt{4-x^2}-2\ln |\dfrac{2+\sqrt{4-x^2}}{x}|+C$
Work Step by Step
Apply formula : $\int \dfrac{\sqrt{a^2-x^2}}{x}dx=\sqrt{a^2-x^2}-a\ln |\dfrac{a+\sqrt{a^2-x^2}}{x}|+C$
Consider $I =\int\dfrac{\sqrt{4-x^2}}{x}dx \\
=\sqrt{4-x^2}-2\ln |\dfrac{2+\sqrt{4-x^2}}{x}|+C$
