Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 8: Techniques of Integration - Section 8.6 - Integral Tables and Computer Algebra Systems - Exercises 8.6 - Page 481: 43

Answer

$-\dfrac{\sin2\theta\cos^42\theta}{10}+\dfrac{\sin2\theta\cos^22\theta}{30}+\dfrac{\sin2\theta}{15}+C$

Work Step by Step

Apply the Reduction Formula $\int\sin^nax\cos^maxdx=-\dfrac{\sin^{n-1}ax\cos^{m+1}ax}{a(m+n)}+\frac{n-1}{m+n}\int\sin^{n-2}ax\cos^m \space (ax) dx$ and $\int\sin^nax\cos^maxdx=\frac{\sin^{n+1}ax\cos^{m-1}ax}{a(m+n)}+\frac{m-1}{m+n}\int\sin^{n}ax\cos^{m-2}axdx$ Let $I=-\dfrac{\sin2\theta\cos^42\theta}{10}+\dfrac{1}{5}\int\cos^32\theta d\theta \\=-\dfrac{\sin2\theta\cos^42\theta}{10}+\dfrac{1}{5}(\dfrac{\sin2\theta\cos^22\theta}{6}+\dfrac{2}{3} \times \int\cos2\theta d\theta) \\=-\dfrac{\sin2\theta\cos^42\theta}{10}+\dfrac{1}{5}(\dfrac{\sin2\theta\cos^22\theta}{6}+\dfrac{2}{3}\times\dfrac{\sin2\theta}{2})+C \\=-\dfrac{\sin2\theta\cos^42\theta}{10}+\dfrac{\sin2\theta\cos^22\theta}{30}+\dfrac{\sin2\theta}{15}+C$
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