Answer
$$\frac{1}{2},\frac{3}{4},\frac{7}{8},\frac{15}{16}$$
Work Step by Step
$a_{n}=\frac{2^{n}-1}{2^{n}}$
$$a_{1}=\frac{2^{1}-1}{2^{1}}=\frac{1}{2}$$
$$a_{2}=\frac{2^{2}-1}{2^{2}}=\frac{3}{4}$$
$$a_{3}=\frac{2^{3}-1}{2^{3}}=\frac{7}{8}$$
$$a_{4}=\frac{2^{4}-1}{2^{4}}=\frac{15}{16}$$
