Answer
$$0,-\frac{1}{4},-\frac{2}{9},-\frac{3}{16}$$
Work Step by Step
We are given the sequence:
$a_{n}=(\frac{1-n}{n^{2}})$
We plug in the various $n$ values to get the first 4 terms:
$$a_{1}=(\frac{1-1}{1^{2}})=0$$
$$a_{2}=\frac{(1-2)}{2^{2}}=-\frac{1}{4}$$
$$a_{3}=\frac{(1-3)}{3^{2}}=-\frac{2}{9}$$
$$a_{4}=\frac{(1-4)}{4^{2}}=-\frac{3}{16}$$
