Answer
$a_n = (-1)^{n+1}(n)^2 $
Work Step by Step
The sequence has squares of positive integers, with alternating signs. so $ (-1)^{n+1}$ gives an alternating sign and $(n)^2$ gives the squares, resulting in the general term of the sequence.
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 10: Infinite Sequences and Series - Section 10.1 - Sequences - Exercises 10.1 - Page 569: 15
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
