Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.1 - Sequences - Exercises 10.1 - Page 569: 13

Answer

$a_n = (-1)^{n+1}$

Work Step by Step

The sequence is always 1 with the sign alternating, the sequence starts at n=1 which gives a -1 just like the sequence in the problem.
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