Answer
$$1,\frac{1}{2},\frac{1}{6},\frac{1}{24}$$
Work Step by Step
$a_{n}=\frac{1}{n!},$ so
$$a_{1}=\frac{1}{1!}=1$$
$$a_{2}=\frac{1}{2!}=\frac{1}{2}$$
$$a_{3}=\frac{1}{3!}=\frac{1}{6}$$
$$a_{4}=\frac{1}{4!}=\frac{1}{24}$$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 10: Infinite Sequences and Series - Section 10.1 - Sequences - Exercises 10.1 - Page 569: 2
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