Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.1 - Sequences - Exercises 10.1 - Page 569: 21

Answer

$a_{n}=4n-3, \quad n=1,2,3...$

Work Step by Step

The differences between terms are $4,4,4,4,...$ This is constant, similar to the sequence of natural numbers: $1,2,3,4,...$ where the difference between terms is $1$. If we multiply each term of $1,2,3,4,...$ with $4$, we get $4,8,12,16,20,24,...$ The difference between terms is now $4$, as in the problem. We find a relationship between this sequence and the one given by the problem by observing the pattern: $ 1=4-3\quad$ = $4n-3$ when $n=1,$ $ 5=8-3\quad$ = $4n-3$ when $n=2,$ $ 9=12-3\quad$ = $4n-3$ when $n=3,$ $ 13=16-3\quad$ = $4n-3$ when $n=4$ $ 17=20-3\quad$ = $4n-3$ when $n=5$ $...$ $a_{n}=4n-3, \quad n=1,2,3...$
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