Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Section 10.1 - Sequences - Exercises 10.1 - Page 569: 4



Work Step by Step

Beacuse $a_{n}=2+(-1)^{n},$ so $$a_{1}=2+(-1)^{1}=2-1=1$$ $$a_{2}=2+(-1)^{2}=2+1=3$$ $$a_{3}=2+(-1)^{3}=2-1=1$$ $$a_{4}=2+(-1)^{4}=2+1=3$$
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