Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 14 - Section 14.2 - Area between Two Curves and Applications - Exercises - Page 1031: 25

Answer

$$A = \frac{3}{{10}}$$

Work Step by Step

$$\eqalign{ & {\text{Let }}f\left( x \right) = x,{\text{ }}g\left( x \right) = {x^4} \cr & {\text{From the graph shown below}} \cr & f\left( x \right) \geqslant g\left( x \right){\text{ on the interval }}0 \leqslant x \leqslant 1 \cr & {\text{The area is given by}} \cr & A = \int_0^1 {\left( {x - {x^4}} \right)} dx \cr & {\text{ Integrate}} \cr & A = \left[ {\frac{1}{2}{x^2} - \frac{1}{5}{x^5}} \right]_0^1 \cr & A = \left[ {\frac{1}{2}{{\left( 1 \right)}^2} - \frac{1}{5}{{\left( 1 \right)}^5}} \right] - \left[ {\frac{1}{2}{{\left( 0 \right)}^2} - \frac{1}{5}{{\left( 0 \right)}^5}} \right] \cr & {\text{Simplifying}} \cr & A = \frac{1}{2} - \frac{1}{5} \cr & A = \frac{3}{{10}} \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.