Answer
$-e^{-x}$
Work Step by Step
(see p. 840, Generalized Rule)$\quad$
$\displaystyle \frac{d}{dx}[e^{u}]=e^{u}\cdot\frac{du}{dx}$
$u(x)=-x$
$\displaystyle \frac{du}{dx}=-1$
$\displaystyle \frac{d}{dx}[e^{-x}]=e^{-x}\cdot(-1)=-e^{-x}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 11 - Section 11.5 - Derivatives of Logarithmic and Exponential Functions - Exercises - Page 842: 9
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