Chapter 11 - Section 11.5 - Derivatives of Logarithmic and Exponential Functions - Exercises - Page 842: 6

$\displaystyle \frac{2}{2x-4}$

$\quad$ $\displaystyle \frac{d}{dx}[\ln|u|]=\frac{1}{u}\cdot\frac{du}{dx}$ $u(x)=2x-4$ $\displaystyle \frac{du}{dx}=2$ $\displaystyle \frac{d}{dx}[\ln|2x-43|]=\frac{1}{2x-4}\cdot 2=\frac{2}{2x-4}$