Chapter 11 - Section 11.5 - Derivatives of Logarithmic and Exponential Functions - Exercises - Page 842: 14

$3^{x^{2}-x}\cdot\ln 3\cdot(2x-1)$

$\quad$ $\displaystyle \frac{d}{dx}[b^{u}]=b^{u}\ln b\cdot\frac{du}{dx}$ $b=3$ $u(x)=x^{2}-x\displaystyle \qquad \frac{du}{dx}=2x-1$ $\displaystyle \frac{d}{dx}[3^{x^{2}-x}]=3^{x^{2}-x}\ln 3\cdot(2x-1)$