Chapter 11 - Section 11.5 - Derivatives of Logarithmic and Exponential Functions - Exercises - Page 842: 21

$\displaystyle \frac{3}{3x-1}$

(see p. 838, Generalized Rule)$\quad$ $\displaystyle \frac{d}{dx}[\ln|u|]=\frac{1}{u}\cdot\frac{du}{dx}$ $u(x)=3x-1$ $\displaystyle \frac{du}{dx}=3$ $\displaystyle \frac{d}{dx}[\ln|3x-1|]=\frac{1}{3x-1}\cdot 3$