Answer
$2 \cdot 3^{2x-4} \ln (3)$
Work Step by Step
We have: $t=3^{2x-4}$,
We will use the generalized power rule:
$\displaystyle \frac{d}{dx}[a^{n}]=na^{n-1}\frac{da}{dx}$
$t^{\prime}(x)=3^{2x-4}\ln (3) \displaystyle \cdot\frac{d}{dx}(2x-4)\\=2 \cdot 3^{2x-4} \ln (3)$
So,
$t^{\prime}(x)=2 \cdot 3^{2x-4} \ln (3)$
