Answer
$f^{\prime}(x)=2e^{2x+1}$
Work Step by Step
Using
$\displaystyle \frac{d}{dx}[e^{u}]=e^{u}\cdot\frac{du}{dx}$,
$u=2x+1,\quad \dfrac{du}{dx}=2$,
$\displaystyle \frac{d}{dx}[e^{2x+1}]=e^{2x+1}\cdot(2)$
$f^{\prime}(x)=2e^{2x+1}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 11 - Section 11.5 - Derivatives of Logarithmic and Exponential Functions - Exercises - Page 842: 51
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