Chapter 11 - Section 11.5 - Derivatives of Logarithmic and Exponential Functions - Exercises - Page 842: 52

$f^{\prime}(x)=4e^{4x-5}$

Using $\displaystyle \frac{d}{dx}[e^{u}]=e^{u}\cdot\frac{du}{dx}$, with $u=4x-5,\displaystyle \quad\frac{du}{dx}=4$ $\displaystyle \frac{d}{dx}[e^{4x-5}]=e^{4x-5}\cdot(4)$ $f^{\prime}(x)=4e^{4x-5}$