Answer
$ -\displaystyle \frac{2}{x-8}$
Work Step by Step
Apply the power rule for logarithms
$s(x)=-2\ln(x-8)$
Apply $\displaystyle \frac{d}{dx}[\ln|u|]=\frac{1}{u}\cdot\frac{du}{dx}$,
with constant multiple,
$s^{\prime}(x)=-2\displaystyle \cdot\frac{1}{x-8}\cdot 1=$
$=-\displaystyle \frac{2}{x-8}$