Answer
$\displaystyle \frac{3}{3x+1}-\frac{4}{4x-2}$
Work Step by Step
Apply the Quotient Rule for logarithms,
$h(x)=\displaystyle \ln[\frac{3x+1}{4x-2}]=\ln(3x+1)-\ln(4x-2)$
Derivative of a logarithm of a function:
$\displaystyle \frac{d}{dx}[\ln u]=\frac{1}{u}\frac{du}{dx}$
$h^{\prime}(x)=\displaystyle \frac{3}{3x+1}-\frac{4}{4x-2}$
