Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 11 - Section 11.5 - Derivatives of Logarithmic and Exponential Functions - Exercises - Page 842: 7

Answer

$e^{x+3}$

Work Step by Step

$\quad$ $\displaystyle \frac{d}{dx}[e^{u}]=e^{u}\cdot\frac{du}{dx}$ $u(x)=x+3$ $\displaystyle \frac{du}{dx}=1$ $\displaystyle \frac{d}{dx}[e^{x+3}]=e^{x+3}\cdot 1=e^{x+3}$
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