Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 40



Work Step by Step

$h=c=\frac{8-0}{2}=4$ $b^2=a^2-c^2=25-16=9$ $\frac{(x-4)^{2}}{25}+\frac{(y+1)^{2}}{9}=1$, This is an equation of an ellipse.
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