Answer
$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{4}=1$ and Foci: $( 2\pm \sqrt 5,1 )$
Work Step by Step
Here, $c^2=a^2-b^2=9-4=5$
$c=\sqrt 5$
Hence, $\frac{(x-2)^2}{9}+\frac{(y-1)^2}{4}=1$ and Foci: $( 2\pm \sqrt 5,1 )$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 18
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