Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 1

Answer

Focus: $(0,\frac{3}{2})$ Directrix: $y=-\frac{3}{2}$
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Work Step by Step

$x^2=6y$ or, $x^2=4(\frac{3}{2})y$ Thus, vertex: $(0,0)$ Focus: $(0,\frac{3}{2})$ Directrix: $y=-\frac{3}{2}$
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