Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 30

Answer

Ellipse vertices: (1±√2,2) foci: (1±1,2) center: (1,2)

Work Step by Step

x²-2x+2y²-8y= -7 (x-1)²-1+2(y²-4y)= -7 (x-1)²-1+2( (y-2)²-4)= -7 (x-1)²-1+2(y-2)²-8= -7 (x-1)²+2(y-2)²=2 ((x-1)²/2)+((y-2)²/1) = 1 from the equation a=√2, b=1 and c = 1 from c²= a²-b² from the equation the center (h,k)=(1,2) and vertices (h±a,k) = (1±√2,2) and foci (h±c,k)= (1±1,2)
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