Answer
vertices: (±1,1)
foci: (±√2,1)
asymptotes: (y-1) = ±x
y= ±x+1
Work Step by Step
x²-(y²-2y)=2
x²-((y-1)²-1)=2
x²-(y-1)²+1=2
x²-(y-1)²=1
thus:
a=1, b=1.
c²=a²+b² = 2
c= √2
the center from equation (h,k) = (0,1)
vertices: (±a+h,k)= (±1,1)
foci: (±c+h,k) = (±√2,1)
asymptotes: (y-k)=±(b/a)(x)
y-1=±x
y= ±x+1
