## Calculus: Early Transcendentals 8th Edition

$\frac{(x)^2}{4}+\frac{y^2}{9}=1$ and Foci: $( 0,\pm \sqrt 5 )$
From the figure, major axis: $a=3$ and minor axis: $b=2$ Therefore, $\frac{(x)^2}{4}+\frac{y^2}{9}=1$ $c^2=a^2-b^2=9-4=5$ $c=\sqrt 5$ Hence, $\frac{(x)^2}{4}+\frac{y^2}{9}=1$ and Foci: $( 0,\pm \sqrt 5 )$