Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 17


$\frac{(x)^2}{4}+\frac{y^2}{9}=1$ and Foci: $( 0,\pm \sqrt 5 )$

Work Step by Step

From the figure, major axis: $a=3$ and minor axis: $b=2$ Therefore, $\frac{(x)^2}{4}+\frac{y^2}{9}=1$ $c^2=a^2-b^2=9-4=5$ $c=\sqrt 5$ Hence, $\frac{(x)^2}{4}+\frac{y^2}{9}=1$ and Foci: $( 0,\pm \sqrt 5 )$
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