Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 10

Answer

Equation of parabola is $(x -2)^2 = 2(y +2)$. Focus: $(2,-\frac{3}{2})$ Directrix : $y=-\frac{5}{2}$

Work Step by Step

If a parabola is oriented upwards, the equation of the parabola is, $(x -h)^2 = 4p(y - k)$. However, if a parabola is oriented laterally, the equation of the parabola is, $(y -h)^2 = 4p(x - k)$. In the equation, the vertex of the parabola is at $(h, k)\ or\ (k,h)$ respectively. The focus is at $(h, k + p)\ or\ (k+p,h)$, respectively. So let us plug in our given points. Vertex: $(2,-2)$ Hence, $p=\frac{1}{2}$ Equation of parabola is $(x -2)^2 = 2(y +2)$. Focus: $(2,-\frac{3}{2})$ Directrix : $y=-\frac{5}{2}$
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