Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 15

Answer

Foci: $( 1, \pm \sqrt 5 )$ Vertices : $( 1,\pm 3)$
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Work Step by Step

$9x^2-18x+4y^2=27$ Rewrite as $\frac{(x-1)^2}{(2)^2}+\frac{y^2}{(3)^2}=1$ $c^2=a^2-b^2=9-4=5$ $c=\sqrt 5$ Foci: $( 1, \pm \sqrt 5 )$ Vertices : $( 1,\pm 3)$
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