Answer
Foci: $( 1, \pm \sqrt 5 )$
Vertices : $( 1,\pm 3)$
Work Step by Step
$9x^2-18x+4y^2=27$
Rewrite as $\frac{(x-1)^2}{(2)^2}+\frac{y^2}{(3)^2}=1$
$c^2=a^2-b^2=9-4=5$ $c=\sqrt 5$
Foci: $( 1, \pm \sqrt 5 )$
Vertices : $( 1,\pm 3)$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 15
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