## Calculus: Early Transcendentals 8th Edition

Foci: $( 1, \pm \sqrt 5 )$ Vertices : $( 1,\pm 3)$
$9x^2-18x+4y^2=27$ Rewrite as $\frac{(x-1)^2}{(2)^2}+\frac{y^2}{(3)^2}=1$ $c^2=a^2-b^2=9-4=5$ $c=\sqrt 5$ Foci: $( 1, \pm \sqrt 5 )$ Vertices : $( 1,\pm 3)$