Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 25


Hyperbola Foci: $( \pm \sqrt 5,0)$ Vertices: $(\pm1,0,)$

Work Step by Step

$4x^2=y^2+4$ $\frac{x^{2}}{1^2}-\frac{y^{2}}{2^2}=1$, the equation of a hyperbola. $c^{2}=1+4=5$ $c=\sqrt 5$ Foci: $( \pm \sqrt 5,0)$ Vertices: $(\pm1,0,)$
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