Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 680: 28

Hyperbola Foci: $( 1,\pm \sqrt 2)$ Vertices: $(1,\pm1,)$

$x^2-2x=y^2-2$ $\frac{(y-0)^{2}}{1^2}-\frac{(x-1)^{2}}{1^2}=1$, the equation of a hyperbola. $c^{2}=1+1=2$ $c=\sqrt 2$ Foci: $( 1,\pm \sqrt 2)$ Vertices: $(1,\pm1)$