Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.4 Exercises - Page 539: 3

Answer

$ 5 \sin{\theta} $

Work Step by Step

$ \int{ \frac{ x^2 }{ \sqrt{25-x^2} } }dx $ has the form $ \sqrt{a^2 - u^2} $ so $ x=a\sin{\theta}, a=5 $ $ x=5\sin{\theta} $
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