Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.4 Exercises - Page 539: 2

Answer

$ 2 \sin {\theta} $

Work Step by Step

$ \int { \sqrt{4-x^2} dx} $ has the form $ \sqrt{a^2-u^2} $ so $ u=a \sin {\theta} $, $ a=2 $ $ u=2 \sin {\theta} $
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