Answer
$ 3\tan{\theta}$
Work Step by Step
$ \int {(9+x^2)^{-2}dx} $ can be written as
$ \int {\frac{1}{\sqrt{9+x^2}^{4}}dx} $ which has the form $ \sqrt{a^2+u^2} $ so
$ x=a\tan{\theta}, a=3 $
$ x=3\tan{\theta} $
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.4 Exercises - Page 539: 1
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