Answer
$f(x)=-3x^2+1$
Work Step by Step
Integrate $f'(x)$:
$\int f'(x) dx=\int (-6x)dx=-3x^2+C$
$f(x)=-3x^2+C$
Set in $f(1)=-2$ and solve for $C$:
$-2=-3(1)^2+C$
$C=-2+3=1$
$f(x)=-3x^2+1$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - Review Exercises - Page 312: 9
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