Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - Review Exercises - Page 312: 7

Answer

$= x^{2} + 9 cosx + c$

Work Step by Step

$\int (2x - 9 sinx) dx$ $= \frac{2x^{2}}{2} - 9(-cosx) + c$ $= x^{2} + 9 cosx + c$
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