Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - Review Exercises - Page 312: 5

Answer

$= \frac{x^{2}}{2} - \frac{4}{x^{2}}+ c$

Work Step by Step

$\int (\frac{x^{4}+8}{x^{3}}) dx$ $\int (\frac{x^{4}}{x^{3}}+ \frac{8}{x^{3}}) dx$ $\int (x + \frac{8}{x^{3}}) dx$ $\int (x + 8x^{-3}) dx$ $= \frac{x^{2}}{2} + \frac{8x^{-2}}{-2}$ $= \frac{x^{2}}{2} + \frac{-2(-4x^{-2})}{-2(1)}$ $= \frac{x^{2}}{2} + -4x^{-2}$ $= \frac{x^{2}}{2} - \frac{4}{x^{2}}+ c$
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