Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - Review Exercises - Page 312: 1

Answer

$\dfrac {x^{2}}{2}-6x+C$

Work Step by Step

$\int \left( x-6\right) dx=\int xdx-\int 6dx=\dfrac {x^{2}}{2}-6x+C$
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