Answer
$\dfrac {4}{3}x^{3}+\dfrac {x^{2}}{2}+3x+C$
Work Step by Step
$\int \left( 4x^{2}+x+3\right) dx=\int 4x^{2}dx+\int xdx+\int 3dx=\dfrac {4}{3}x^{3}+\dfrac {x^{2}}{2}+3x+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - Review Exercises - Page 312: 3
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