Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - Review Exercises: 3

Answer

$\dfrac {4}{3}x^{3}+\dfrac {x^{2}}{2}+3x+C$

Work Step by Step

$\int \left( 4x^{2}+x+3\right) dx=\int 4x^{2}dx+\int xdx+\int 3dx=\dfrac {4}{3}x^{3}+\dfrac {x^{2}}{2}+3x+C$
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